NCERT Exercise 7.1 - Q9 - Coordinate Geometry
Question: If Q(0, 1) is equidistant from P(5, -3) and R(x, 6), find the values of x. Also find the distances QR and PR. Q(0, 1) P(5, -3) R1(4, 6) R2(-4, 6) X Y
Answer: x = +-4, QR = sqrt(41), PR = 9*sqrt(2) or sqrt(82).
Full step-by-step NCERT solution with diagrams on Something by Zero.