NCERT Exercise 4.27 - Chemical Bonding and Molecular Structure
Question: Show formation of double and triple bonds in C2H4 and C2H2.
Answer: C2H4 has one C-C sigma bond from sp2-sp2 overlap and one pi bond from parallel p-p overlap. C2H2 has one C-C sigma bond from sp-sp overlap and two mutually perpendicular pi bonds from p-p overlap.
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