NCERT Problem 5.5 - Chemical Thermodynamics

Question: For vaporisation of 1 mol water at 100 degrees C and 1 bar, delta H = 41 kJ mol^-1. Calculate delta U.

Answer: delta U = delta H - delta n_g RT = 41.0 - (1)(8.314 x 10^-3)(373) = about 37.9 kJ mol^-1.

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