NCERT Problem 5.6 - Chemical Thermodynamics
Question: Find heat released when 1 g graphite burns in a bomb calorimeter from 298 K to 299 K, given calorimeter heat capacity.
Answer: At constant volume, q_v = delta U = -C_cal delta T for the reaction; divide by moles of carbon to obtain molar delta U, then use delta H = delta U + delta n_g RT.
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