NCERT Problem 5.12 - Chemical Thermodynamics

Question: For 3/2 O2(g) -> O3(g) at 298 K, K = 2.47 x 10^-29. Find delta G degrees.

Answer: delta G degrees = -RT ln K = +163 kJ mol^-1 (approximately).

Full step-by-step NCERT solution with diagrams on Something by Zero.

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