NCERT Exercise 9.19 - Mechanical Properties of Fluids

Question: Find pressure inside a mercury drop of radius 3.00 mm. S_Hg = 4.65 x 10^-1 N m^-1, P_a = 1.01 x 10^5 Pa.

Answer: Total pressure = **about 1.0131 x 10^5 Pa**; excess pressure = **310 Pa**.

Full step-by-step NCERT solution with diagrams on Something by Zero.