NCERT Example 8.4 - Mechanical Properties of Solids
Question: A square lead slab (50 cm side, 10 cm thick) has its lower edge riveted. A 9.0 x 10^4 N shearing force is applied to the narrow face. Find displacement. G_lead = 5.6 x 10^9 N m^-2.
Answer: Displacement = **1.6 x 10^-4 m = 0.16 mm**.
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