NCERT Exercise 5.2 - Work, Energy and Power
Question: A 2 kg body starts from rest under a 7 N horizontal force on a table with kinetic-friction coefficient 0.1. Find the work done in 10 s by applied force, friction, net force, and the change in kinetic energy.
Answer: W_applied = **882 J**; W_friction = **-247 J**; W_net = Delta K = **635 J** (approximately).
Full step-by-step NCERT solution with diagrams on Something by Zero.