NCERT Exercise 3.23 - Chemical Kinetics
Question: The rate constant for the decomposition of hydrocarbons is 2.418 × 10–5s–1 at 546 K. If the energy of activation is 179.9 kJ/mol, what will be the value of pre-exponential factor.
Answer: **NCERT answer:** 3.9 × 10 12 s –1
Full step-by-step NCERT solution with diagrams on Something by Zero.