NCERT Exercise 2.5 - Electrochemistry
Question: Calculate the emf of the cell in which the following reaction takes place: Ni(s) + 2Ag+(0.002 M) -> Ni2+(0.160 M) + 2Ag(s). Given E°cell = 1.05 V.
Answer: E = 1.05 - (0.059/2) log(0.160/(0.002)^2) = **0.91 V**.
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