NCERT Exercise 9.5 Q15 - Differential Equations
Question: Find the particular solution of dy/dx - 3 y cot x = sin 2x; y=2 when x=π/2.
Answer: y = 4 sin^3 x - 2 sin^2 x.
Full step-by-step NCERT solution with diagrams on Something by Zero.
Question: Find the particular solution of dy/dx - 3 y cot x = sin 2x; y=2 when x=π/2.
Answer: y = 4 sin^3 x - 2 sin^2 x.
Full step-by-step NCERT solution with diagrams on Something by Zero.