NCERT Example 7 - Differential Equations
Question: Find the equation of the curve through (1,1) with differential equation x dy = (2x^2 + 1) dx (x != 0).
Answer: y = x^2 + log|x|.
Full step-by-step NCERT solution with diagrams on Something by Zero.
Question: Find the equation of the curve through (1,1) with differential equation x dy = (2x^2 + 1) dx (x != 0).
Answer: y = x^2 + log|x|.
Full step-by-step NCERT solution with diagrams on Something by Zero.