NCERT Exercise 7.3 Q3 - Integrals
Question: Find int cos 2x cos 4x cos 6x dx.
Answer: (1/8)[x + (1/4) sin 4x + (1/8) sin 8x + (1/12) sin 12x] + C
Full step-by-step NCERT solution with diagrams on Something by Zero.
Question: Find int cos 2x cos 4x cos 6x dx.
Answer: (1/8)[x + (1/4) sin 4x + (1/8) sin 8x + (1/12) sin 12x] + C
Full step-by-step NCERT solution with diagrams on Something by Zero.