NCERT Exercise 7.3 Q6 - Integrals
Question: Find int sin x sin 2x sin 3x dx.
Answer: (1/4) cos 2x - (1/8) cos 4x - (1/12) cos 6x + C
Full step-by-step NCERT solution with diagrams on Something by Zero.
Question: Find int sin x sin 2x sin 3x dx.
Answer: (1/4) cos 2x - (1/8) cos 4x - (1/12) cos 6x + C
Full step-by-step NCERT solution with diagrams on Something by Zero.