NCERT Exercise 12.1 Q2 - Linear Programming
Question: Minimise Z = −3x + 4y subject to x + 2y ≤ 8, 3x + 2y ≤ 12, x ≥ 0, y ≥ 0.
Answer: Minimum Z = −12 at (4, 0).
Full step-by-step NCERT solution with diagrams on Something by Zero.
Question: Minimise Z = −3x + 4y subject to x + 2y ≤ 8, 3x + 2y ≤ 12, x ≥ 0, y ≥ 0.
Answer: Minimum Z = −12 at (4, 0).
Full step-by-step NCERT solution with diagrams on Something by Zero.