NCERT Exercise 12.1 Q4 - Linear Programming
Question: Minimise Z = 3x + 5y subject to x + 3y ≥ 3, x + y ≥ 2, x ≥ 0, y ≥ 0.
Answer: Minimum Z = 7 at (3/2, 1/2).
Full step-by-step NCERT solution with diagrams on Something by Zero.
Question: Minimise Z = 3x + 5y subject to x + 3y ≥ 3, x + y ≥ 2, x ≥ 0, y ≥ 0.
Answer: Minimum Z = 7 at (3/2, 1/2).
Full step-by-step NCERT solution with diagrams on Something by Zero.