NCERT Exercise 12.1 Q7 - Linear Programming

Question: Minimise and maximise Z = 5x + 10y subject to x + 2y ≤ 120, x + y ≥ 60, x − 2y ≥ 0, x ≥ 0, y ≥ 0.

Answer: Minimum Z = 300 at (60, 0); maximum Z = 600 at every point of the segment joining (120, 0) and (60, 30).

Full step-by-step NCERT solution with diagrams on Something by Zero.

All Chapter 12 solutions