NCERT Exercise 12.1 Q8 - Linear Programming

Question: Minimise and maximise Z = x + 2y subject to x + 2y ≥ 100, 2x − y ≤ 0, 2x + y ≤ 200, x ≥ 0, y ≥ 0.

Answer: Minimum Z = 100 at every point of the segment joining (0, 50) and (20, 40); maximum Z = 400 at (0, 200).

Full step-by-step NCERT solution with diagrams on Something by Zero.

All Chapter 12 solutions