NCERT Example 2 - Linear Programming
Question: Minimise Z = 200x + 500y subject to x + 2y ≥ 10, 3x + 4y ≤ 24, x ≥ 0, y ≥ 0, graphically.
Answer: Minimum Z = 2300 at (4, 3).
Full step-by-step NCERT solution with diagrams on Something by Zero.
Question: Minimise Z = 200x + 500y subject to x + 2y ≥ 10, 3x + 4y ≤ 24, x ≥ 0, y ≥ 0, graphically.
Answer: Minimum Z = 2300 at (4, 3).
Full step-by-step NCERT solution with diagrams on Something by Zero.