NCERT Exercise 2.5 - Electrostatic Potential and Capacitance
Question: A parallel plate capacitor with air between the plates has a capacitance of 8 pF (1 pF = 10⁻¹² F). What will be the capacitance if the distance between the plates is reduced by half, and the space between them is filled with a substance of dielectric constant 6?
Answer: New capacitance = **96 pF**.
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