NCERT Exercise 7.1 Q8 - Triangles
Question: In right triangle ABC, right angled at C, M is the mid-point of hypotenuse AB. C is joined to M and produced to a point D such that DM = CM. Point D is joined to point B (see Fig. 7.23). Show that: (i) ∆AMC ≅ ∆BMD (ii) ∠DBC is a right angle. (iii) ∆DBC ≅ ∆ACB (iv) CM = ½AB.
Answer: (i) ∆AMC ≅ ∆BMD by SAS. (ii) ∠DBC = 90°. (iii) ∆DBC ≅ ∆ACB. (iv) CM = ½AB.
Full step-by-step NCERT solution with diagrams on Something by Zero.